x^2=7x+6x^2-570

Solution for x^2=7x+6x^2-570 equation:

x^2=7x+6x^2-570

We move all terms to the left:

x^2-(7x+6x^2-570)=0

We get rid of parentheses

x^2-6x^2-7x+570=0

We add all the numbers together, and all the variables

-5x^2-7x+570=0

a = -5; b = -7; c = +570;
Δ = b2-4ac
Δ = -72-4·(-5)·570
Δ = 11449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11449}=107$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-107}{2*-5}=\frac{-100}{-10}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+107}{2*-5}=\frac{114}{-10}
=-11+2/5
$